Difference between revisions of "Physical / geometric interpretation of complex integration"

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where <math> {\bf T} </math>  and <math> {\bf N} </math>  are, respectively, the unit tangent and the unit normal vectors to the curve <math> \gamma.</math>
 
where <math> {\bf T} </math>  and <math> {\bf N} </math>  are, respectively, the unit tangent and the unit normal vectors to the curve <math> \gamma.</math>
  
This computation shows that <math> {\rm Re}\left(\int _\gamma f(z)\, dz\right) </math>
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This computation shows that <math> {\rm Re}\left(\int _\gamma f(z)\, dz\right) </math> can be interpreted as the flow of the vector field <math> {\bf F} </math>  along <math> \gamma </math>, while <math> {\rm Im}\left(\int _\gamma f(z)\, dz\right) </math> can be interpreted as the flux of <math> {\bf F} </math>  across <math> \gamma </math>.

Latest revision as of 11:23, 21 December 2021

There are many geometric and physical interpretations of integrals of real-valued functions (such as are, volume, work etc.). However, a similar interpretation is rarely discussed for complex contour integral. The following interpretation of contour integration is due to Pólya (George Pólya and Gordon Latta, Complex Variables, Wiley, 1974.)

Let [math]\displaystyle{ \gamma }[/math] be a simple closed smooth curve in the complex plane, and [math]\displaystyle{ f }[/math] be a (complex-valued) function defined on [math]\displaystyle{ \gamma }[/math]. Parametrize [math]\displaystyle{ \gamma }[/math] with arc length [math]\displaystyle{ s }[/math], such that [math]\displaystyle{ \gamma(s) = x(s) + y(s). }[/math] As usual, have [math]\displaystyle{ f(z) = u(z) + iv(z) = u(x,y) + iv(x,y) }[/math]. Consider a vector field

[math]\displaystyle{ {\bf F} (x,y) = [u(x,y), -v(x,y)]. }[/math]

We have:

[math]\displaystyle{ \int _\gamma f(z)\, dz = \int_0^l f(\gamma(s) ) \gamma' (s) \, ds = \int_0^l (u(\gamma(s) +i v(\gamma(s))(x'(s) + i y'(s)) \, ds= }[/math]

[math]\displaystyle{ = \int_0^l \left (u(\gamma(s))x'(s) - v(\gamma(s)) y'(s)\right) \, ds + i \int_0^l \left (u(\gamma(s))y'(s) + v(\gamma(s)) x'(s)\right) \, ds = }[/math]

[math]\displaystyle{ = \int_0^l [u(\gamma(s), -v(\gamma(s)] \cdot [x'(s), y'(s)] \, ds + i \int_0^l [u(\gamma(s)), -v(\gamma(s)]\cdot [y'(s), -x'(s)] \, ds = }[/math]

[math]\displaystyle{ = \int_0^l {\bf F}(\gamma(s)) \cdot {\bf T}(\gamma (s)) \, ds + i \int_0^l {\bf F}(\gamma (s))\cdot {\bf N}(\gamma (s)) \, ds = }[/math]

[math]\displaystyle{ = \int_\gamma {\bf F } \cdot {\bf T}\, d\gamma + i \int_\gamma \bf{F} \cdot {\bf N}\, d\gamma, }[/math]

where [math]\displaystyle{ {\bf T} }[/math] and [math]\displaystyle{ {\bf N} }[/math] are, respectively, the unit tangent and the unit normal vectors to the curve [math]\displaystyle{ \gamma. }[/math]

This computation shows that [math]\displaystyle{ {\rm Re}\left(\int _\gamma f(z)\, dz\right) }[/math] can be interpreted as the flow of the vector field [math]\displaystyle{ {\bf F} }[/math] along [math]\displaystyle{ \gamma }[/math], while [math]\displaystyle{ {\rm Im}\left(\int _\gamma f(z)\, dz\right) }[/math] can be interpreted as the flux of [math]\displaystyle{ {\bf F} }[/math] across [math]\displaystyle{ \gamma }[/math].