Difference between revisions of "Derivative rules via approximations"

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<math> h(x) = f(x) + g(x)\approx = \left[ f(a) + f'(a) (x-a) \right] + \left[ g(a) + g'(a) (x-a) \right] = \left[f(a) +g(a)\rigth]+ \left[f'(a) +g'(a)](x-a) </math>.  Since <math> h(a) = f(a) +g(a) </math>, we obtain <math> h(x)\approx h(a) + {\color{red}\left[ f'(a)+g'(a)\right]} (x-a) </math>. Comparing it with <math> h(x)\approx h(a) + {\color{red} h'(a)} (x-a)</math> we conclude that <math> h'(a) = f'(a)+g'(a)</math>, or (replacing $a$ with an arbitrary variable):
  
<math> g(x) = f(x) \approx =k \left[ f(a) + f'(a) (x-a) \right] = kf(a) + kf'(a) (x-a) </math>.  Since <math> g(a) = kf(a) </math>, we obtain <math> g(x)\approx g(a) + {\color{red} kf'(a)} (x-a) </math>. Comparing it with <math> g(x)\approx g(a) + {\color{red} g'(a)} (x-a)</math> we conclude that <math> g'(a) = k f'(a)</math>, or (replacing $a$ with an arbitrary variable):
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<math> \boxed{(f(x)+g(x))' = f'(x)+g'(x)} </math>
 
 
<math> \boxed{(kf(x))' = kf'(x)} </math>
 
  
 
Product rule.
 
Product rule.
 
Chain rule.
 
Chain rule.

Revision as of 10:40, 21 November 2021

The fact that the derivative [math]\displaystyle{ f'(a) }[/math] exists can be written as [math]\displaystyle{ f(x) \approx f(a) + f'(a) (x-a) }[/math] for all [math]\displaystyle{ x }[/math] that are near [math]\displaystyle{ a }[/math]. This is known as linear approximation (or linearization) of f at the number a. Various rules for differentiation can be derived using linear approximation.


Constant multiple rule. Let [math]\displaystyle{ h(x) = k f(x) }[/math], where [math]\displaystyle{ k }[/math] is a constant. Then for all [math]\displaystyle{ x }[/math] near [math]\displaystyle{ a }[/math] we have [math]\displaystyle{ g(x) = kf(x) \approx k \left[ f(a) + f'(a) (x-a) \right] = kf(a) + kf'(a) (x-a). }[/math] Since [math]\displaystyle{ g(a) = kf(a) }[/math], we obtain [math]\displaystyle{ g(x)\approx g(a) + {\color{red} kf'(a)} (x-a) }[/math]. Comparing it with [math]\displaystyle{ g(x)\approx g(a) + {\color{red} g'(a)} (x-a) }[/math] we conclude that [math]\displaystyle{ g'(a) = k f'(a) }[/math], or (replacing [math]\displaystyle{ a }[/math] with an arbitrary variable):

[math]\displaystyle{ \boxed{(kf(x))' = kf'(x)} }[/math]


Sum/Difference rule. Let [math]\displaystyle{ h(x) = f(x) + g(x) }[/math]. For all [math]\displaystyle{ x }[/math] near [math]\displaystyle{ a }[/math] we have


[math]\displaystyle{  h(x) = f(x) + g(x)\approx = \left[ f(a) + f'(a) (x-a) \right] + \left[ g(a) + g'(a) (x-a) \right] = \left[f(a) +g(a)\rigth]+ \left[f'(a) +g'(a)](x-a)  }[/math].  Since [math]\displaystyle{  h(a) = f(a) +g(a)  }[/math], we obtain [math]\displaystyle{  h(x)\approx h(a) + {\color{red}\left[ f'(a)+g'(a)\right]} (x-a)  }[/math]. Comparing it with [math]\displaystyle{  h(x)\approx h(a) + {\color{red} h'(a)} (x-a) }[/math] we conclude that [math]\displaystyle{  h'(a) = f'(a)+g'(a) }[/math], or (replacing $a$ with an arbitrary variable):

[math]\displaystyle{ \boxed{(f(x)+g(x))' = f'(x)+g'(x)} }[/math]

Product rule. Chain rule.